Fix deleting a user that has a prior subscription (#3533)

(for real this time)

apps/labrinth/src/database/models/user_item.rs

@@ -1,8 +1,11 @@
 use super::ids::{ProjectId, UserId};
 use super::{CollectionId, ReportId, ThreadId};
 use crate::database::models;
+use crate::database::models::charge_item::ChargeItem;
+use crate::database::models::user_subscription_item::UserSubscriptionItem;
 use crate::database::models::{DatabaseError, OrganizationId};
 use crate::database::redis::RedisPool;
+use crate::models::billing::ChargeStatus;
 use crate::models::users::Badges;
 use ariadne::ids::base62_impl::{parse_base62, to_base62};
 use chrono::{DateTime, Utc};
@@ -657,9 +660,26 @@ impl User {
             .execute(&mut **transaction)
             .await?;
 
+            let open_subscriptions =
+                UserSubscriptionItem::get_all_user(id, &mut **transaction)
+                    .await?;
+
+            for x in open_subscriptions {
+                let charge =
+                    ChargeItem::get_open_subscription(x.id, &mut **transaction)
+                        .await?;
+                if let Some(mut charge) = charge {
+                    charge.status = ChargeStatus::Cancelled;
+                    charge.due = Utc::now();
+                    charge.user_id = deleted_user;
+
+                    charge.upsert(transaction).await?;
+                }
+            }
+
             sqlx::query!(
                 "
-                UPDATE charges
+                UPDATE users_subscriptions
                 SET user_id = $1
                 WHERE user_id = $2
                 ",